What are the solutions to the equation 3x^3-17x^2+18x+8=0 ?

The solutions to the equation 3x^3-17x^2+18x+8=0 are x=2,x=-1/3 ,x=4

Find the zeros of 3x^3-17x^2+18x+8=0

The zeros of 3x^3-17x^2+18x+8=0 are x=2,x=-1/3 ,x=4

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3 x^{3} - 17 x^{2} + 18 x + 8 = 0

x = 2, x = - \frac{1}{3}, x = 4

Decimal Notation

x = 2, x = - 0.33333 \dots, x = 4

Solution steps

3 x^{3} - 17 x^{2} + 18 x + 8 = 0

Factor

3 x^{3} - 17 x^{2} + 18 x + 8 : (x - 2) (3 x + 1) (x - 4)

(x - 2) (3 x + 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x + 1 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = - \frac{1}{3}, x = 4

f, f x = 4 x^{3} - 6 x^{2}

x (2 x^{2} - 41) = 225

i x^{4} + x^{2} - i = 0

x^{2} (x + 1)^{2} + x^{2} = 3 (x + 1)^{2}

x^{3} - x = x^{2} + 5 x - 6

What are the solutions to the equation 3x^3-17x^2+18x+8=0 ?
The solutions to the equation 3x^3-17x^2+18x+8=0 are x=2,x=-1/3 ,x=4
Find the zeros of 3x^3-17x^2+18x+8=0
The zeros of 3x^3-17x^2+18x+8=0 are x=2,x=-1/3 ,x=4