What are the solutions to the equation x^3-4x^2-3x+6=0 ?

The solutions to the equation x^3-4x^2-3x+6=0 are x=1,x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2

Find the zeros of x^3-4x^2-3x+6=0

The zeros of x^3-4x^2-3x+6=0 are x=1,x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2

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x^{3} - 4 x^{2} - 3 x + 6 = 0

x = 1, x = \frac{3 + 33}{2}, x = \frac{3 - 33}{2}

Decimal Notation

x = 1, x = 4.37228 \dots, x = - 1.37228 \dots

Solution steps

x^{3} - 4 x^{2} - 3 x + 6 = 0

Factor

x^{3} - 4 x^{2} - 3 x + 6 : (x - 1) (x^{2} - 3 x - 6)

(x - 1) (x^{2} - 3 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 3 x - 6 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 3 x - 6 = 0 : x = \frac{3 + 33}{2}, x = \frac{3 - 33}{2}

The solutions are

x = 1, x = \frac{3 + 33}{2}, x = \frac{3 - 33}{2}

2 x^{4} - x^{3} - 14 x^{2} + 19 x - 6 = 0

- 3 x^{4} + 15 x^{2} - 12 = 0

x^{11} + x^{3} = 2

4 x^{3} + 7 x^{2} - 28 x - 49 = 0

4 x^{3} - 72 x^{2} + 420 x - 784 = 0

What are the solutions to the equation x^3-4x^2-3x+6=0 ?
The solutions to the equation x^3-4x^2-3x+6=0 are x=1,x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2
Find the zeros of x^3-4x^2-3x+6=0
The zeros of x^3-4x^2-3x+6=0 are x=1,x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2