What are the solutions to the equation 4x^3+7x^2-28x-49=0 ?

The solutions to the equation 4x^3+7x^2-28x-49=0 are x=-7/4 ,x=-sqrt(7),x=sqrt(7)

Find the zeros of 4x^3+7x^2-28x-49=0

The zeros of 4x^3+7x^2-28x-49=0 are x=-7/4 ,x=-sqrt(7),x=sqrt(7)

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4 x^{3} + 7 x^{2} - 28 x - 49 = 0

x = - \frac{7}{4}, x = - 7, x = 7

Decimal Notation

x = - 1.75, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

4 x^{3} + 7 x^{2} - 28 x - 49 = 0

Factor

4 x^{3} + 7 x^{2} - 28 x - 49 : (4 x + 7) (x + 7) (x - 7)

(4 x + 7) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 7 = 0 or x + 7 = 0 or x - 7 = 0

Solve

4 x + 7 = 0 : x = - \frac{7}{4}

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = - \frac{7}{4}, x = - 7, x = 7

4 x^{3} - 72 x^{2} + 420 x - 784 = 0

0 = 4 x^{4} - 9 x^{2}

r^{3} - 3 r + 2 = 0

z^{5} = 1 - i

(1 - p)^{15} = 0

What are the solutions to the equation 4x^3+7x^2-28x-49=0 ?
The solutions to the equation 4x^3+7x^2-28x-49=0 are x=-7/4 ,x=-sqrt(7),x=sqrt(7)
Find the zeros of 4x^3+7x^2-28x-49=0
The zeros of 4x^3+7x^2-28x-49=0 are x=-7/4 ,x=-sqrt(7),x=sqrt(7)