What are the solutions to the equation x^3+5x^2+9x+5=0 ?

The solutions to the equation x^3+5x^2+9x+5=0 are x=-1,x=-2+i,x=-2-i

Find the zeros of x^3+5x^2+9x+5=0

The zeros of x^3+5x^2+9x+5=0 are x=-1,x=-2+i,x=-2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + 5 x^{2} + 9 x + 5 = 0

x = - 1, x = - 2 + i, x = - 2 - i

Solution steps

x^{3} + 5 x^{2} + 9 x + 5 = 0

Factor

x^{3} + 5 x^{2} + 9 x + 5 : (x + 1) (x^{2} + 4 x + 5)

(x + 1) (x^{2} + 4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 4 x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 4 x + 5 = 0 : x = - 2 + i, x = - 2 - i

The solutions are

x = - 1, x = - 2 + i, x = - 2 - i

- x^{3} + 5 x^{2} - 8 x + 4

x^{3} + 3 x^{2} - 4 x - 12 = 0

x^{3} - \frac{5}{6} x^{2} + \frac{35}{6} x + 1 = 0

6 x^{5} - 4 x^{3} = - 1

z^{12} = 1

What are the solutions to the equation x^3+5x^2+9x+5=0 ?
The solutions to the equation x^3+5x^2+9x+5=0 are x=-1,x=-2+i,x=-2-i
Find the zeros of x^3+5x^2+9x+5=0
The zeros of x^3+5x^2+9x+5=0 are x=-1,x=-2+i,x=-2-i