What are the solutions to the equation (x-1)(x^2+6x+9)=5(x+3) ?

The solutions to the equation (x-1)(x^2+6x+9)=5(x+3) are x=-3,x=2,x=-4

Find the zeros of (x-1)(x^2+6x+9)=5(x+3)

The zeros of (x-1)(x^2+6x+9)=5(x+3) are x=-3,x=2,x=-4

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(x - 1) (x^{2} + 6 x + 9) = 5 (x + 3)

x = - 3, x = 2, x = - 4

Solution steps

(x - 1) (x^{2} + 6 x + 9) = 5 (x + 3)

Move

5 (x + 3)

to the left side

(x - 1) (x^{2} + 6 x + 9) - 5 (x + 3) = 0

Factor

(x - 1) (x^{2} + 6 x + 9) - 5 (x + 3) : (x + 3) (x - 2) (x + 4)

(x + 3) (x - 2) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 2 = 0 or x + 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 2 = 0 : x = 2

Solve

x + 4 = 0 : x = - 4

The solutions are

x = - 3, x = 2, x = - 4

x^{3} - 5 x^{2} + 25 x - 125 = 0

8 x^{7} = 9 x^{8}

5 (x - 1) = 5 (x^{5} + 2)

x^{3} + 13 x^{2} + 57 x + 85 = 0

w^{6} = - 27

What are the solutions to the equation (x-1)(x^2+6x+9)=5(x+3) ?
The solutions to the equation (x-1)(x^2+6x+9)=5(x+3) are x=-3,x=2,x=-4
Find the zeros of (x-1)(x^2+6x+9)=5(x+3)
The zeros of (x-1)(x^2+6x+9)=5(x+3) are x=-3,x=2,x=-4