What are the solutions to the equation x^3-5x^2+25x-125=0 ?

The solutions to the equation x^3-5x^2+25x-125=0 are x=5,x=5i,x=-5i

Find the zeros of x^3-5x^2+25x-125=0

The zeros of x^3-5x^2+25x-125=0 are x=5,x=5i,x=-5i

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x^{3} - 5 x^{2} + 25 x - 125 = 0

x = 5, x = 5 i, x = - 5 i

Solution steps

x^{3} - 5 x^{2} + 25 x - 125 = 0

Factor

x^{3} - 5 x^{2} + 25 x - 125 : (x - 5) (x^{2} + 25)

(x - 5) (x^{2} + 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x^{2} + 25 = 0

Solve

x - 5 = 0 : x = 5

Solve

x^{2} + 25 = 0 : x = 5 i, x = - 5 i

The solutions are

x = 5, x = 5 i, x = - 5 i

8 x^{7} = 9 x^{8}

5 (x - 1) = 5 (x^{5} + 2)

x^{3} + 13 x^{2} + 57 x + 85 = 0

w^{6} = - 27

0 = x (x - 4)^{3}

What are the solutions to the equation x^3-5x^2+25x-125=0 ?
The solutions to the equation x^3-5x^2+25x-125=0 are x=5,x=5i,x=-5i
Find the zeros of x^3-5x^2+25x-125=0
The zeros of x^3-5x^2+25x-125=0 are x=5,x=5i,x=-5i