What are the solutions to the equation 0=x(x-4)^3 ?

The solutions to the equation 0=x(x-4)^3 are x=0,x=4

Find the zeros of 0=x(x-4)^3

The zeros of 0=x(x-4)^3 are x=0,x=4

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0 = x (x - 4)^{3}

x = 0, x = 4

Solution steps

0 = x (x - 4)^{3}

Switch sides

x (x - 4)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = 4

4 x^{3} = 108

- x (x + 9) (x^{2} - 9) = 0

2 x^{4} - 9 x^{3} + 6 x^{2} + 11 x - 6 = 0

x^{4} - 2 x^{3} + 5 x^{2} - 8 x + 4 = 0

\frac{x ^{3}}{7} - 21 x = 0

What are the solutions to the equation 0=x(x-4)^3 ?
The solutions to the equation 0=x(x-4)^3 are x=0,x=4
Find the zeros of 0=x(x-4)^3
The zeros of 0=x(x-4)^3 are x=0,x=4