What are the solutions to the equation solvefor x,2=x^4+x^2 ?

The solutions to the equation solvefor x,2=x^4+x^2 are x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of solvefor x,2=x^4+x^2

The zeros of solvefor x,2=x^4+x^2 are x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i

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solve for

x, 2 = x^{4} + x^{2}

x = 1, x = - 1, x = 2 i, x = - 2 i

Solution steps

2 = x^{4} + x^{2}

Switch sides

x^{4} + x^{2} = 2

Move

2

to the left side

x^{4} + x^{2} - 2 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} + u - 2 = 0

Solve

u^{2} + u - 2 = 0 : u = 1, u = - 2

u = 1, u = - 2

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = - 2 : x = 2 i, x = - 2 i

The solutions are

x = 1, x = - 1, x = 2 i, x = - 2 i

x^{4} - x^{3} - 13 x^{2} + x + 12 = 0

s^{3} + 10.6 s^{2} + 7 s + 10 = 0

x^{4} - 4 x^{3} + 5 x^{2} - 2 x - 2

x^{3} - 9 x^{2} + 21 x - 5 = 0

200 x - 0.02 x^{2} - 0.000002 x^{3} - 80000 = 0

What are the solutions to the equation solvefor x,2=x^4+x^2 ?
The solutions to the equation solvefor x,2=x^4+x^2 are x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of solvefor x,2=x^4+x^2
The zeros of solvefor x,2=x^4+x^2 are x=1,x=-1,x=sqrt(2)i,x=-sqrt(2)i