What are the solutions to the equation x^4-x^3-13x^2+x+12=0 ?

The solutions to the equation x^4-x^3-13x^2+x+12=0 are x=-1,x=1,x=-3,x=4

Find the zeros of x^4-x^3-13x^2+x+12=0

The zeros of x^4-x^3-13x^2+x+12=0 are x=-1,x=1,x=-3,x=4

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x^{4} - x^{3} - 13 x^{2} + x + 12 = 0

x = - 1, x = 1, x = - 3, x = 4

Solution steps

x^{4} - x^{3} - 13 x^{2} + x + 12 = 0

Factor

x^{4} - x^{3} - 13 x^{2} + x + 12 : (x + 1) (x - 1) (x + 3) (x - 4)

(x + 1) (x - 1) (x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x + 3 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 1, x = 1, x = - 3, x = 4

s^{3} + 10.6 s^{2} + 7 s + 10 = 0

x^{4} - 4 x^{3} + 5 x^{2} - 2 x - 2

x^{3} - 9 x^{2} + 21 x - 5 = 0

200 x - 0.02 x^{2} - 0.000002 x^{3} - 80000 = 0

(1 + 12 x^{2})^{3} = 0

What are the solutions to the equation x^4-x^3-13x^2+x+12=0 ?
The solutions to the equation x^4-x^3-13x^2+x+12=0 are x=-1,x=1,x=-3,x=4
Find the zeros of x^4-x^3-13x^2+x+12=0
The zeros of x^4-x^3-13x^2+x+12=0 are x=-1,x=1,x=-3,x=4