What are the solutions to the equation 2x^4+4x^3-18x^2-36x=0 ?

The solutions to the equation 2x^4+4x^3-18x^2-36x=0 are x=0,x=-2,x=-3,x=3

Find the zeros of 2x^4+4x^3-18x^2-36x=0

The zeros of 2x^4+4x^3-18x^2-36x=0 are x=0,x=-2,x=-3,x=3

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2 x^{4} + 4 x^{3} - 18 x^{2} - 36 x = 0

x = 0, x = - 2, x = - 3, x = 3

Solution steps

2 x^{4} + 4 x^{3} - 18 x^{2} - 36 x = 0

Factor

2 x^{4} + 4 x^{3} - 18 x^{2} - 36 x : 2 x (x + 2) (x + 3) (x - 3)

2 x (x + 2) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 2, x = - 3, x = 3

8 x^{3} + 50 x^{2} - 41 x + 7 = 0

9 x^{3} + 12 x^{2} + 4 x = 0

x^{4} - x^{3} - x^{2} - x - 1 = 0

x^{3} + 2 x^{2} + 4 x + 8

c^{3} + 2 c = 3

What are the solutions to the equation 2x^4+4x^3-18x^2-36x=0 ?
The solutions to the equation 2x^4+4x^3-18x^2-36x=0 are x=0,x=-2,x=-3,x=3
Find the zeros of 2x^4+4x^3-18x^2-36x=0
The zeros of 2x^4+4x^3-18x^2-36x=0 are x=0,x=-2,x=-3,x=3