What are the solutions to the equation (1+x)^{10}= 1000/910 ?

The solutions to the equation (1+x)^{10}= 1000/910 are x=\sqrt[10]{100/91}-1,x=-\sqrt[10]{100/91}-1

Find the zeros of (1+x)^{10}= 1000/910

The zeros of (1+x)^{10}= 1000/910 are x=\sqrt[10]{100/91}-1,x=-\sqrt[10]{100/91}-1

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(1 + x)^{10} = \frac{1000}{910}

Decimal Notation

x = 0.00947 \dots, x = - 2.00947 \dots

Solution steps

(1 + x)^{10} = \frac{1000}{910}

Cancel the common factor:

10

(1 + x)^{10} = \frac{100}{91}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

3 (1 + g)^{4} = 3.7

a, a^{4} - t^{4} = 6 a^{2} t

3 x^{4} - 8 x^{2} = - 4

x^{2} 5 x + 1 = 3 x^{2} + 6

7 x^{4} - 112 = 0

What are the solutions to the equation (1+x)^{10}= 1000/910 ?
The solutions to the equation (1+x)^{10}= 1000/910 are x=\sqrt[10]{100/91}-1,x=-\sqrt[10]{100/91}-1
Find the zeros of (1+x)^{10}= 1000/910
The zeros of (1+x)^{10}= 1000/910 are x=\sqrt[10]{100/91}-1,x=-\sqrt[10]{100/91}-1