What are the solutions to the equation 16x^4-x^2=0 ?

The solutions to the equation 16x^4-x^2=0 are x= 1/4 ,x=-1/4 ,x=0

Find the zeros of 16x^4-x^2=0

The zeros of 16x^4-x^2=0 are x= 1/4 ,x=-1/4 ,x=0

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16 x^{4} - x^{2} = 0

x = \frac{1}{4}, x = - \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = - 0.25, x = 0

Solution steps

16 x^{4} - x^{2} = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

16 u^{2} - u = 0

Solve

16 u^{2} - u = 0 : u = \frac{1}{16}, u = 0

u = \frac{1}{16}, u = 0

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{1}{16} : x = \frac{1}{4}, x = - \frac{1}{4}

Solve

x^{2} = 0 : x = 0

The solutions are

x = \frac{1}{4}, x = - \frac{1}{4}, x = 0

x^{3} - 3 x^{2} - 10 x + 24

\frac{Q ^{3}}{3} - 10 Q^{2} + 80 Q + 648 = 4 Q

x^{3} + x^{2} - 17 x + 15

x^{3} - x^{2} - 25 x + 25 = 0

- 19 x^{3} - 12 x^{2} + 16 x = 0

What are the solutions to the equation 16x^4-x^2=0 ?
The solutions to the equation 16x^4-x^2=0 are x= 1/4 ,x=-1/4 ,x=0
Find the zeros of 16x^4-x^2=0
The zeros of 16x^4-x^2=0 are x= 1/4 ,x=-1/4 ,x=0