What are the solutions to the equation 7x^6+35x^4=42x^5 ?

The solutions to the equation 7x^6+35x^4=42x^5 are x=0,x=1,x=5

Find the zeros of 7x^6+35x^4=42x^5

The zeros of 7x^6+35x^4=42x^5 are x=0,x=1,x=5

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7 x^{6} + 35 x^{4} = 42 x^{5}

x = 0, x = 1, x = 5

Solution steps

7 x^{6} + 35 x^{4} = 42 x^{5}

Move

42 x^{5}

to the left side

7 x^{6} + 35 x^{4} - 42 x^{5} = 0

Factor

7 x^{6} + 35 x^{4} - 42 x^{5} : 7 x^{4} (x - 1) (x - 5)

7 x^{4} (x - 1) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 5 = 0 : x = 5

The solutions are

x = 0, x = 1, x = 5

- 2 x (- x^{2} + 12) = 0

5 x + 21 = 10 x^{19}

x^{4} - 2 x^{3} - 8 x^{2} + 18 x - 9 = 0

7 x^{3} - 35 x^{2} - 252 x = 0

y^{3} = 64 y

What are the solutions to the equation 7x^6+35x^4=42x^5 ?
The solutions to the equation 7x^6+35x^4=42x^5 are x=0,x=1,x=5
Find the zeros of 7x^6+35x^4=42x^5
The zeros of 7x^6+35x^4=42x^5 are x=0,x=1,x=5