What are the solutions to the equation 7x^4=20x^2 ?

The solutions to the equation 7x^4=20x^2 are x=0,x=-(2sqrt(5))/(sqrt(7)),x=(2sqrt(5))/(sqrt(7))

Find the zeros of 7x^4=20x^2

The zeros of 7x^4=20x^2 are x=0,x=-(2sqrt(5))/(sqrt(7)),x=(2sqrt(5))/(sqrt(7))

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7 x^{4} = 20 x^{2}

x = 0, x = - \frac{2 5}{7}, x = \frac{2 5}{7}

Decimal Notation

x = 0, x = - 1.69030 \dots, x = 1.69030 \dots

Solution steps

7 x^{4} = 20 x^{2}

Move

20 x^{2}

to the left side

7 x^{4} - 20 x^{2} = 0

Factor

7 x^{4} - 20 x^{2} : x^{2} (7 x + 25) (7 x - 25)

x^{2} (7 x + 25) (7 x - 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 7 x + 25 = 0 or 7 x - 25 = 0

Solve

7 x + 25 = 0 : x = - \frac{2 5}{7}

Solve

7 x - 25 = 0 : x = \frac{2 5}{7}

The solutions are

x = 0, x = - \frac{2 5}{7}, x = \frac{2 5}{7}

- 4 x^{3} + 3 x^{2} + 2 x = 0

0 = 4 x^{3} - 4

v^{3} - 4 v = 0

4 x^{3} - 256 x = 0

x, x^{3} + y^{3} + z^{3} = 42

What are the solutions to the equation 7x^4=20x^2 ?
The solutions to the equation 7x^4=20x^2 are x=0,x=-(2sqrt(5))/(sqrt(7)),x=(2sqrt(5))/(sqrt(7))
Find the zeros of 7x^4=20x^2
The zeros of 7x^4=20x^2 are x=0,x=-(2sqrt(5))/(sqrt(7)),x=(2sqrt(5))/(sqrt(7))