What are the solutions to the equation roots 12x^3-28x^2-9x+10 ?

The solutions to the equation roots 12x^3-28x^2-9x+10 are x= 1/2 ,x=-2/3 ,x= 5/2

Find the zeros of roots 12x^3-28x^2-9x+10

The zeros of roots 12x^3-28x^2-9x+10 are x= 1/2 ,x=-2/3 ,x= 5/2

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roots

12 x^{3} - 28 x^{2} - 9 x + 10

x = \frac{1}{2}, x = - \frac{2}{3}, x = \frac{5}{2}

Solution steps

12 x^{3} - 28 x^{2} - 9 x + 10

The roots are the intercepts with the x-axis

(y = 0)

12 x^{3} - 28 x^{2} - 9 x + 10 = 0

Factor

12 x^{3} - 28 x^{2} - 9 x + 10 : (2 x - 1) (3 x + 2) (2 x - 5)

(2 x - 1) (3 x + 2) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 3 x + 2 = 0 or 2 x - 5 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions are

x = \frac{1}{2}, x = - \frac{2}{3}, x = \frac{5}{2}

c^{3} = 27

6 x^{3} - 35 x^{2} + 26 x - 5 = 0

480 = \frac{4}{3} π r^{3}

r^{4} - r = 0

y^{4} + 2 y^{3} + y^{2} + 8 y - 12 = 0

What are the solutions to the equation roots 12x^3-28x^2-9x+10 ?
The solutions to the equation roots 12x^3-28x^2-9x+10 are x= 1/2 ,x=-2/3 ,x= 5/2
Find the zeros of roots 12x^3-28x^2-9x+10
The zeros of roots 12x^3-28x^2-9x+10 are x= 1/2 ,x=-2/3 ,x= 5/2