What are the solutions to the equation x^4+2x^2-63=0 ?

The solutions to the equation x^4+2x^2-63=0 are x=sqrt(7),x=-sqrt(7),x=3i,x=-3i

Find the zeros of x^4+2x^2-63=0

The zeros of x^4+2x^2-63=0 are x=sqrt(7),x=-sqrt(7),x=3i,x=-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} + 2 x^{2} - 63 = 0

x = 7, x = - 7, x = 3 i, x = - 3 i

Solution steps

x^{4} + 2 x^{2} - 63 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} + 2 u - 63 = 0

Solve

u^{2} + 2 u - 63 = 0 : u = 7, u = - 9

u = 7, u = - 9

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 7 : x = 7, x = - 7

Solve

x^{2} = - 9 : x = 3 i, x = - 3 i

The solutions are

x = 7, x = - 7, x = 3 i, x = - 3 i

(2 x^{2} + 7 x - 8) (2 x^{2} + 7 x - 3) - 6 = 0

16 x^{3} + 28 x^{2} = 0

m^{4} + m^{3} + m^{2} = 0

m, 17 n^{2} + 29 m^{3} = 5492346

14 x (x^{2} - 4)^{6} = 0

What are the solutions to the equation x^4+2x^2-63=0 ?
The solutions to the equation x^4+2x^2-63=0 are x=sqrt(7),x=-sqrt(7),x=3i,x=-3i
Find the zeros of x^4+2x^2-63=0
The zeros of x^4+2x^2-63=0 are x=sqrt(7),x=-sqrt(7),x=3i,x=-3i