What is the answer to solvefor b,x=(-b+sqrt(b^2-4ac))/(2a) ?

The answer to solvefor b,x=(-b+sqrt(b^2-4ac))/(2a) is b=-(ax^2+c)/x

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solvefor b,x=(-b+sqrt(b^2-4ac))/(2a)

solve for

b, x = \frac{- b + b ^{2} - 4 a c}{2 a}

b = - \frac{a x ^{2} + c}{x}

Solution steps

x = \frac{- b + b ^{2} - 4 a c}{2 a}

Multiply both sides by

2 a

x \cdot 2 a = \frac{- b + b ^{2} - 4 a c}{2 a} \cdot 2 a

Simplify

x \cdot 2 a = - b + b^{2} - 4 a c

Remove square roots

4 a^{2} x^{2} + 4 ba x + b^{2} = b^{2} - 4 a c

Solve

4 a^{2} x^{2} + 4 ba x + b^{2} = b^{2} - 4 a c : b = - \frac{a x ^{2} + c}{x}

b = - \frac{a x ^{2} + c}{x}

x^{2} - 8 x + 3 x - 2 = 20 + 3 x - 2

3 x + 45 + 1 = 7

3 x + 1 + x + 2 = 3

5 x + 39 + 6 = 8

What is the answer to solvefor b,x=(-b+sqrt(b^2-4ac))/(2a) ?
The answer to solvefor b,x=(-b+sqrt(b^2-4ac))/(2a) is b=-(ax^2+c)/x