What is the answer to sqrt(x^2+2x+5)+sqrt(x^2+2x)=5 ?

The answer to sqrt(x^2+2x+5)+sqrt(x^2+2x)=5 is x=-1+sqrt(5),x=-1-sqrt(5)

Solve for x: sqrt(x^2+2x+5)+sqrt(x^2+2x)=5

The solution is x=-1+sqrt(5),x=-1-sqrt(5)

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x^{2} + 2 x + 5 + x^{2} + 2 x = 5

x = - 1 + 5, x = - 1 - 5

Decimal Notation

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

x^{2} + 2 x + 5 + x^{2} + 2 x = 5

Remove square roots

400 = 100 x^{2} + 200 x

Solve

400 = 100 x^{2} + 200 x : x = - 1 + 5, x = - 1 - 5

x = - 1 + 5, x = - 1 - 5

Verify Solutions:

x = - 1 + 5

True

, x = - 1 - 5

True

The solutions are

x = - 1 + 5, x = - 1 - 5

2 x + 2 - x - 1 = 2

5 x + 56 - 3 = 1

x - 6 + 20 = 21

y, x y - 4 y^{2} = 12

- \frac{x}{4 - x ^{2}} = 0

What is the answer to sqrt(x^2+2x+5)+sqrt(x^2+2x)=5 ?
The answer to sqrt(x^2+2x+5)+sqrt(x^2+2x)=5 is x=-1+sqrt(5),x=-1-sqrt(5)
Solve for x: sqrt(x^2+2x+5)+sqrt(x^2+2x)=5
The solution is x=-1+sqrt(5),x=-1-sqrt(5)