What is the answer to sqrt(x-4)=sqrt(x-3)-sqrt(2x-1) ?

The answer to sqrt(x-4)=sqrt(x-3)-sqrt(2x-1) is No Solution for x\in\mathbb{R}

Solve for x: sqrt(x-4)=sqrt(x-3)-sqrt(2x-1)

The solution is No Solution for x\in\mathbb{R}

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x - 4 = x - 3 - 2 x - 1

No Solution for x \in R

Solution steps

x - 4 = x - 3 - 2 x - 1

Remove square roots

4 x^{2} = 8 x^{2} - 28 x + 12

Solve

4 x^{2} = 8 x^{2} - 28 x + 12 : x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

x = \frac{7 + 37}{2}, x = \frac{7 - 37}{2}

Verify Solutions:

x = \frac{7 + 37}{2}

False

, x = \frac{7 - 37}{2}

False

The solution is

No Solution for x \in R

y, x + y = 4

11 n + 3 = 6

- 5 = (x + 7)^{\frac{1}{2}} - 11

x^{2} - 7 = - 2 x - 6

21 - 5 x = x - 5

What is the answer to sqrt(x-4)=sqrt(x-3)-sqrt(2x-1) ?
The answer to sqrt(x-4)=sqrt(x-3)-sqrt(2x-1) is No Solution for x\in\mathbb{R}
Solve for x: sqrt(x-4)=sqrt(x-3)-sqrt(2x-1)
The solution is No Solution for x\in\mathbb{R}