What are the solutions to the equation x^2-20x+99=0 ?

The solutions to the equation x^2-20x+99=0 are x=11,x=9

Find the zeros of x^2-20x+99=0

The zeros of x^2-20x+99=0 are x=11,x=9

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x^{2} - 20 x + 99 = 0

x = 11, x = 9

Solution steps

x^{2} - 20 x + 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 99}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 99 = 2

x_{1, 2} = \frac{- ( - 20 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2}{2 \cdot 1} : 11

x = \frac{- ( - 20 ) - 2}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 11, x = 9

\frac{3}{2} \cdot 7

- 4 x^{2} - 32 x + 36

∣ 7 x - 7 ∣ + 4 < 7

(1 + 0.25 x) (x^{1}) - ((- 0.25 x) (- 1)) = 0

3 (x - 1) = - 3

What are the solutions to the equation x^2-20x+99=0 ?
The solutions to the equation x^2-20x+99=0 are x=11,x=9
Find the zeros of x^2-20x+99=0
The zeros of x^2-20x+99=0 are x=11,x=9