What is the answer to cube root of 2+x}-\sqrt[3]{2-x}=\sqrt[3]{4 ?

The answer to cube root of 2+x}-\sqrt[3]{2-x}=\sqrt[3]{4 is x=2

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cube root of 2+x}-\sqrt[3]{2-x}=\sqrt[3]{4

x = 2

Solution steps

Rewrite the equation with

and

x = u^{3} - 2

Solve

u \approx 1.58740 \dots

Substitute back

solve for

x

Solve

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

\frac{x ^{\frac{3}{2}}}{x - 6} = x - 8

x^{\frac{3}{2}} + 4 = 0

x - 1 + 5 = 9

x + 1 = 3 x - 1

3 x - 5 + x - 1 = 2

What is the answer to cube root of 2+x}-\sqrt[3]{2-x}=\sqrt[3]{4 ?
The answer to cube root of 2+x}-\sqrt[3]{2-x}=\sqrt[3]{4 is x=2
Solve for x: cube root of 2+x}-\sqrt[3]{2-x}=\sqrt[3]{4
The solution is x=2