What is the answer to 0=1-1/3 t^{-2/3} ?

The answer to 0=1-1/3 t^{-2/3} is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))

Solve for t: 0=1-1/3 t^{-2/3}

The solution is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))

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0 = 1 - \frac{1}{3} t^{- \frac{2}{3}}

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

Decimal Notation

t = 0.19245 \dots, t = - 0.19245 \dots

Solution steps

0 = 1 - \frac{1}{3} t^{- \frac{2}{3}}

Multiply both sides by

3

0 \cdot 3 = 1 \cdot 3 - \frac{1}{3} t^{- \frac{2}{3}} \cdot 3

Simplify

0 = 3 - t^{- \frac{2}{3}}

Expand

3 - t^{- \frac{2}{3}} : 3 - \frac{1}{t ^{\frac{2}{3}}}

0 = 3 - \frac{1}{t ^{\frac{2}{3}}}

Remove roots

- 27 = - \frac{1}{t ^{2}}

Solve

- 27 = - \frac{1}{t ^{2}} : t = \frac{1}{3 3}, t = - \frac{1}{3 3}

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

Verify Solutions:

t = \frac{1}{3 3}

True

, t = - \frac{1}{3 3}

True

The solutions are

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

2 x - \frac{16}{x} = 0

\frac{1}{1 - x ^{2}} = \frac{π}{3}

g, v = 2 g h

x x - 8 = 3

What is the answer to 0=1-1/3 t^{-2/3} ?
The answer to 0=1-1/3 t^{-2/3} is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))
Solve for t: 0=1-1/3 t^{-2/3}
The solution is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))