What is the answer to solvefor x,\sqrt[3]{x+2}-sqrt(x+2)=0 ?

The answer to solvefor x,\sqrt[3]{x+2}-sqrt(x+2)=0 is x=-1,x=-2

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solvefor x,\sqrt[3]{x+2}-sqrt(x+2)=0

x = - 1, x = - 2

Solution steps

Remove roots

(x + 2)^{2} = (x + 2)^{3}

Solve

(x + 2)^{2} = (x + 2)^{3} : x = - 1, x = - 2

x = - 1, x = - 2

Verify Solutions:

x = - 1

True

, x = - 2

True

The solutions are

x = - 1, x = - 2

4 x - 32 - 16 = - 14

3 x^{\frac{2}{3}} + x^{\frac{1}{3}} - 2 = 0

x + 14 - 2 x + 5 = 1

y, x y = x^{2} + y^{2}

y, x + y + 2 = 2 x + 2 y

What is the answer to solvefor x,\sqrt[3]{x+2}-sqrt(x+2)=0 ?
The answer to solvefor x,\sqrt[3]{x+2}-sqrt(x+2)=0 is x=-1,x=-2