What is the answer to \sqrt[3]{x-2}+sqrt(x+8)=2 ?

The answer to \sqrt[3]{x-2}+sqrt(x+8)=2 is x=1

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\sqrt[3]{x-2}+sqrt(x+8)=2

x = 1

Solution steps

Rewrite the equation with

and

x = u^{3} + 2

u + (u^{3} + 2) + 8 = 2

Solve

u + (u^{3} + 2) + 8 = 2 : u = - 1

u = - 1

Substitute back

solve for

x

Solve

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

2 x + 5 = 3 x - 1

y, x^{\frac{1}{2}} + y^{\frac{1}{2}} = 16

x - 1 = 7

x, \frac{( y ^{3} + y x ^{2} - 4 x )}{x + 1} = 0

x^{2} + 3 x + 5 = 3

What is the answer to \sqrt[3]{x-2}+sqrt(x+8)=2 ?
The answer to \sqrt[3]{x-2}+sqrt(x+8)=2 is x=1
Solve for x: \sqrt[3]{x-2}+sqrt(x+8)=2
The solution is x=1