What are the solutions to the equation -9x(10-2x)=-3x^2 ?

The solutions to the equation -9x(10-2x)=-3x^2 are x=0,x= 30/7

Find the zeros of -9x(10-2x)=-3x^2

The zeros of -9x(10-2x)=-3x^2 are x=0,x= 30/7

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- 9 x (10 - 2 x) = - 3 x^{2}

x = 0, x = \frac{30}{7}

Solution steps

- 9 x (10 - 2 x) = - 3 x^{2}

Move

3 x^{2}

to the left side

- 9 x (10 - 2 x) + 3 x^{2} = 0

Factor

- 9 x (10 - 2 x) + 3 x^{2} : 3 x (7 x - 30)

3 x (7 x - 30) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 7 x - 30 = 0

Solve

7 x - 30 = 0 : x = \frac{30}{7}

The solutions to the quadratic equation are:

x = 0, x = \frac{30}{7}

\frac{1}{6} x + \frac{2}{3} = \frac{1}{4} x - \frac{1}{3}

\frac{3}{4} + \frac{1}{16}

\frac{x}{3} = 0

(2 x + 3)^{2} = 49

x^{4} + 13 x^{3} - 30 x^{2}

What are the solutions to the equation -9x(10-2x)=-3x^2 ?
The solutions to the equation -9x(10-2x)=-3x^2 are x=0,x= 30/7
Find the zeros of -9x(10-2x)=-3x^2
The zeros of -9x(10-2x)=-3x^2 are x=0,x= 30/7