What are the solutions to the equation (2x+3)^2=49 ?

The solutions to the equation (2x+3)^2=49 are x=2,x=-5

Find the zeros of (2x+3)^2=49

The zeros of (2x+3)^2=49 are x=2,x=-5

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(2 x + 3)^{2} = 49

x = 2, x = - 5

Solution steps

(2 x + 3)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 49 : x = 2

Solve

2 x + 3 = - 49 : x = - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

x^{4} + 13 x^{3} - 30 x^{2}

343 x^{3} + 216 y^{3}

2 y^{2} - 7 y + 5

x^{2} - 17 x - 60

- 3 (x + 1) + \frac{9}{10} = 9

What are the solutions to the equation (2x+3)^2=49 ?
The solutions to the equation (2x+3)^2=49 are x=2,x=-5
Find the zeros of (2x+3)^2=49
The zeros of (2x+3)^2=49 are x=2,x=-5