What is the answer to (9-2x^2)/(sqrt(9-x^2))=0 ?

The answer to (9-2x^2)/(sqrt(9-x^2))=0 is x= 3/(sqrt(2)),x=-3/(sqrt(2))

Solve for x: (9-2x^2)/(sqrt(9-x^2))=0

The solution is x= 3/(sqrt(2)),x=-3/(sqrt(2))

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\frac{9 - 2 x ^{2}}{9 - x ^{2}} = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

\frac{9 - 2 x ^{2}}{9 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

9 - 2 x^{2} = 0

Solve

9 - 2 x^{2} = 0 : x = \frac{3}{2}, x = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

, x = - \frac{3}{2}

True

The solutions are

x = \frac{3}{2}, x = - \frac{3}{2}

2 x = x + 5 - 1

4 x - 9 = 2 x - 4

6 m - 38 = m - 5

y, (y + 1 - 1)^{2} - 2 = x

What is the answer to (9-2x^2)/(sqrt(9-x^2))=0 ?
The answer to (9-2x^2)/(sqrt(9-x^2))=0 is x= 3/(sqrt(2)),x=-3/(sqrt(2))
Solve for x: (9-2x^2)/(sqrt(9-x^2))=0
The solution is x= 3/(sqrt(2)),x=-3/(sqrt(2))