What is the answer to (19x^2-20x+1)/(9x^{8/9)}=0 ?

The answer to (19x^2-20x+1)/(9x^{8/9)}=0 is x=1,x= 1/19

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(19x^2-20x+1)/(9x^{8/9)}=0

\frac{19 x ^{2} - 20 x + 1}{9 x ^{\frac{8}{9}}} = 0

x = 1, x = \frac{1}{19}

Decimal Notation

x = 1, x = 0.05263 \dots

Solution steps

\frac{19 x ^{2} - 20 x + 1}{9 x ^{\frac{8}{9}}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

19 x^{2} - 20 x + 1 = 0

Solve

19 x^{2} - 20 x + 1 = 0 : x = 1, x = \frac{1}{19}

x = 1, x = \frac{1}{19}

Verify Solutions:

x = 1

True

, x = \frac{1}{19}

True

The solutions are

x = 1, x = \frac{1}{19}

2 x + 3 = 6

4 = x - x + 2

x^{2} - 4 x - 5 = 2 x - 10

2 y + 1 + y - 2 y + 1 - y = 2

x - 6 x^{\frac{1}{2}} + 4 = - 5

What is the answer to (19x^2-20x+1)/(9x^{8/9)}=0 ?
The answer to (19x^2-20x+1)/(9x^{8/9)}=0 is x=1,x= 1/19
Solve for x: (19x^2-20x+1)/(9x^{8/9)}=0
The solution is x=1,x= 1/19