What is the answer to cube root of 4-2x}=\sqrt[6]{8x^2-16x ?

The answer to cube root of 4-2x}=\sqrt[6]{8x^2-16x is x=2,x=-2

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cube root of 4-2x}=\sqrt[6]{8x^2-16x

x = 2, x = - 2

Solution steps

Take both sides of the equation to the power of

6 : (4 - 2 x)^{2} = 8 x^{2} - 16 x

(4 - 2 x)^{2} = 8 x^{2} - 16 x

Solve

(4 - 2 x)^{2} = 8 x^{2} - 16 x : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

x^{2} + 2 x + x^{2} + 2 x + 10 - 20 = 0

2624 x^{2} + 1240 x + 25600 = 260

x^{- \frac{1}{2}} = \frac{1}{x}

3 x^{2} + 8 x + 5 = 33 x^{2} + 76 x + 35

(\frac{x}{1 + x ^{2}}) = 2 - 1

What is the answer to cube root of 4-2x}=\sqrt[6]{8x^2-16x ?
The answer to cube root of 4-2x}=\sqrt[6]{8x^2-16x is x=2,x=-2
Solve for x: cube root of 4-2x}=\sqrt[6]{8x^2-16x
The solution is x=2,x=-2