What are the solutions to the equation n^2-5=-4 ?

The solutions to the equation n^2-5=-4 are n=1,n=-1

Find the zeros of n^2-5=-4

The zeros of n^2-5=-4 are n=1,n=-1

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n^{2} - 5 = - 4

n = 1, n = - 1

Solution steps

n^{2} - 5 = - 4

Move

5

to the right side

n^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 1, n = - 1

1 = 1

- 1 = - 1

n = 1, n = - 1

3 x^{2} + 6 x - 24 = 0

7 x - 4 + 3 x = 2 x - 4 + 16

\frac{4.5 \cdot 1 0 ^{- 9}}{8.85 \cdot 1 0 ^{- 12}}

32 m^{2} + 8 m = - 3 m^{2} - 3 m + 6

What are the solutions to the equation n^2-5=-4 ?
The solutions to the equation n^2-5=-4 are n=1,n=-1
Find the zeros of n^2-5=-4
The zeros of n^2-5=-4 are n=1,n=-1