What is the answer to \sqrt[3]{x}=-x^2 ?

The answer to \sqrt[3]{x}=-x^2 is x=0,x=-1

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\sqrt[3]{x}=-x^2

3 x = - x^{2}

x = 0, x = - 1

Solution steps

3 x = - x^{2}

Take both sides of the equation to the power of

3 : x = - x^{6}

x = - x^{6}

Solve

x = - x^{6} : x = 0, x = - 1

x = 0, x = - 1

Verify Solutions:

x = 0

True

, x = - 1

True

The solutions are

x = 0, x = - 1

6 x + 16 - 2 x + 4 = 2

a - x

2 x - 1 + 2 = 5

\frac{1}{1 - x ^{2}} - 2 = 0

x - x^{2} - 3 = x - 1

What is the answer to \sqrt[3]{x}=-x^2 ?
The answer to \sqrt[3]{x}=-x^2 is x=0,x=-1
Solve for x: \sqrt[3]{x}=-x^2
The solution is x=0,x=-1