What is the answer to sqrt(1+3x)=sqrt(x+8)+1 ?

The answer to sqrt(1+3x)=sqrt(x+8)+1 is x=8

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sqrt(1+3x)=sqrt(x+8)+1

1 + 3 x = x + 8 + 1

x = 8

Solution steps

1 + 3 x = x + 8 + 1

Remove square roots

4 x^{2} - 32 x + 64 = 4 x + 32

Solve

4 x^{2} - 32 x + 64 = 4 x + 32 : x = 8, x = 1

x = 8, x = 1

Verify Solutions:

x = 8

True

, x = 1

False

The solution is

x = 8

1 = \frac{x}{9 - x ^{2}}

15 - 2 x = 3

x + 2 2 x + 3 = 3

\frac{4 x - 2}{3 x ^{\frac{2}{3}}} = 0

x - 4 = - x + 6

What is the answer to sqrt(1+3x)=sqrt(x+8)+1 ?
The answer to sqrt(1+3x)=sqrt(x+8)+1 is x=8
Solve for x: sqrt(1+3x)=sqrt(x+8)+1
The solution is x=8