What is the answer to sqrt(2x-x^2)=1-x ?

The answer to sqrt(2x-x^2)=1-x is x=(2-sqrt(2))/2

Solve for x: sqrt(2x-x^2)=1-x

The solution is x=(2-sqrt(2))/2

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2 x - x^{2} = 1 - x

x = \frac{2 - 2}{2}

Decimal Notation

x = 0.29289 \dots

Solution steps

2 x - x^{2} = 1 - x

Square both sides:

2 x - x^{2} = 1 - 2 x + x^{2}

2 x - x^{2} = 1 - 2 x + x^{2}

Solve

2 x - x^{2} = 1 - 2 x + x^{2} : x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

Verify Solutions:

x = \frac{2 + 2}{2}

False

, x = \frac{2 - 2}{2}

True

The solution is

x = \frac{2 - 2}{2}

39 - x = x + 3

1 - x = x^{3} + 3 x^{2} + 3 x + 2

3 3 x - 1 = 2 3 (2 x - 1)

\frac{x + 5 - 4}{2 x + 1 - 2} = - 1

x - 5 = - 2 x + 18

What is the answer to sqrt(2x-x^2)=1-x ?
The answer to sqrt(2x-x^2)=1-x is x=(2-sqrt(2))/2
Solve for x: sqrt(2x-x^2)=1-x
The solution is x=(2-sqrt(2))/2