What is the answer to solvefor F,q=sqrt(Fd+4) ?

The answer to solvefor F,q=sqrt(Fd+4) is F=(q^2-4)/d

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor F,q=sqrt(Fd+4)

solve for

F, q = F d + 4

F = \frac{q ^{2} - 4}{d}

Solution steps

q = F d + 4

Square both sides:

q^{2} = F d + 4

q^{2} = F d + 4

Solve

q^{2} = F d + 4 : F = \frac{q ^{2} - 4}{d}

F = \frac{q ^{2} - 4}{d}

2 u^{\frac{2}{3}} + 7 u^{\frac{1}{3}} = 4

x, \frac{u ( x )}{u ( x ) ^{2} + 1} = x

x + 2 = 2 x + 7

x + 1 + 1 = 0

1 = \frac{1}{3 x ^{\frac{2}{3}}}

What is the answer to solvefor F,q=sqrt(Fd+4) ?
The answer to solvefor F,q=sqrt(Fd+4) is F=(q^2-4)/d