What is the answer to 1= 1/(3x^{2/3)} ?

The answer to 1= 1/(3x^{2/3)} is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))

Solve for x: 1= 1/(3x^{2/3)}

The solution is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))

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1 = \frac{1}{3 x ^{\frac{2}{3}}}

x = \frac{1}{3 3}, x = - \frac{1}{3 3}

Decimal

x = 0.19245 \dots, x = - 0.19245 \dots

Solution steps

1 = \frac{1}{3 x ^{\frac{2}{3}}}

Multiply both sides by

3 x^{\frac{2}{3}}

1 \cdot 3 x^{\frac{2}{3}} = \frac{1}{3 x ^{\frac{2}{3}}} \cdot 3 x^{\frac{2}{3}}

Simplify

3 x^{\frac{2}{3}} = 1

Divide both sides by

3

x^{\frac{2}{3}} = \frac{1}{3}

Take both sides of the equation to the power of

3 : x^{2} = \frac{1}{27}

x^{2} = \frac{1}{27}

Solve

x^{2} = \frac{1}{27} : x = \frac{1}{3 3}, x = - \frac{1}{3 3}

x = \frac{1}{3 3}, x = - \frac{1}{3 3}

Verify Solutions:

x = \frac{1}{3 3}

True

, x = - \frac{1}{3 3}

True

The solutions are

x = \frac{1}{3 3}, x = - \frac{1}{3 3}

x - 1 = x - 3

2 - x^{2} + 4 - x^{2} = 2 x

\frac{37 - 2 x ^{2}}{37 - x ^{2}} = 0

4 x + 9 = x + 1

- 4 = - 4 - 4 - p

What is the answer to 1= 1/(3x^{2/3)} ?
The answer to 1= 1/(3x^{2/3)} is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))
Solve for x: 1= 1/(3x^{2/3)}
The solution is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))