What is the answer to solvefor x,16x-40x^{1/2}+9=0 ?

The answer to solvefor x,16x-40x^{1/2}+9=0 is x= 81/16 ,x= 1/16

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solvefor x,16x-40x^{1/2}+9=0

x, 16 x - 40 x^{\frac{1}{2}} + 9 = 0

x = \frac{81}{16}, x = \frac{1}{16}

Decimal

x = 5.0625, x = 0.0625

Solution steps

16 x - 40 x^{\frac{1}{2}} + 9 = 0

Remove square roots

1600 x = 256 x^{2} + 288 x + 81

Solve

1600 x = 256 x^{2} + 288 x + 81 : x = \frac{81}{16}, x = \frac{1}{16}

x = \frac{81}{16}, x = \frac{1}{16}

Verify Solutions:

x = \frac{81}{16}

True

, x = \frac{1}{16}

True

The solutions are

x = \frac{81}{16}, x = \frac{1}{16}

a, (2 - j 3) = a + jb

x = 8 x - 9

4 x + 8 = 4 2 x - 2

\frac{1}{x} = 1

x + 9 + x = 9

What is the answer to solvefor x,16x-40x^{1/2}+9=0 ?
The answer to solvefor x,16x-40x^{1/2}+9=0 is x= 81/16 ,x= 1/16