What is the answer to sqrt(x^2-2x)-3=1-x ?

The answer to sqrt(x^2-2x)-3=1-x is x= 8/3

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sqrt(x^2-2x)-3=1-x

x^{2} - 2 x - 3 = 1 - x

x = \frac{8}{3}

Decimal

x = 2.66666 \dots

Solution steps

x^{2} - 2 x - 3 = 1 - x

Remove square roots

x^{2} - 2 x = x^{2} - 8 x + 16

Solve

x^{2} - 2 x = x^{2} - 8 x + 16 : x = \frac{8}{3}

x = \frac{8}{3}

Verify Solutions:

x = \frac{8}{3}

True

The solution is

x = \frac{8}{3}

9 x + 2 = 7 x + 18

x + 2 = 10

3 + x^{2} - 3 = x^{2}

x - x = x

2 x - 1 = 1 - 2 x

What is the answer to sqrt(x^2-2x)-3=1-x ?
The answer to sqrt(x^2-2x)-3=1-x is x= 8/3
Solve for x: sqrt(x^2-2x)-3=1-x
The solution is x= 8/3