What is the answer to log_{1/7}(7-x)=-2 ?

The answer to log_{1/7}(7-x)=-2 is x=-42

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log_{1/7}(7-x)=-2

lo g_{\frac{1}{7}} (7 - x) = - 2

x = - 42

Solution steps

lo g_{\frac{1}{7}} (7 - x) = - 2

Apply log rules

7 - x = 49

Solve

7 - x = 49 : x = - 42

x = - 42

2 lo g_{7} (- 2 x) = 0

lo g_{10} (x - 15) - 2 = - lo g_{10} (x)

lo g_{10} (x) + lo g_{10} (x + 3) = 1

lo g_{0.25} (x) = \frac{5}{2}

lo g_{2} (x - 3) = 4

What is the answer to log_{1/7}(7-x)=-2 ?
The answer to log_{1/7}(7-x)=-2 is x=-42
Solve for x: log_{1/7}(7-x)=-2
The solution is x=-42