What is the answer to ln(x-1/2)+ln(2)=2ln(x) ?

The answer to ln(x-1/2)+ln(2)=2ln(x) is x=1

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ln(x-1/2)+ln(2)=2ln(x)

ln (x - \frac{1}{2}) + ln (2) = 2 ln (x)

x = 1

Solution steps

ln (x - \frac{1}{2}) + ln (2) = 2 ln (x)

Apply log rules

(x - \frac{1}{2}) \cdot 2 = x^{2}

Solve

(x - \frac{1}{2}) \cdot 2 = x^{2} : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{10} (- x) + lo g_{10} (1 - 2 x) = 1

lo g_{7} (2 x + 1) = 2

lo g_{a} (216) = 3

lo g_{3} (11 - 4 x) = 3

lo g_{10} (3 x - 2) = 2

What is the answer to ln(x-1/2)+ln(2)=2ln(x) ?
The answer to ln(x-1/2)+ln(2)=2ln(x) is x=1
Solve for x: ln(x-1/2)+ln(2)=2ln(x)
The solution is x=1