What is the answer to ln(x^2)+1=0 ?

The answer to ln(x^2)+1=0 is x=sqrt(1/e),x=-sqrt(1/e)

Solve for x: ln(x^2)+1=0

The solution is x=sqrt(1/e),x=-sqrt(1/e)

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ln (x^{2}) + 1 = 0

x = \frac{1}{e}, x = - \frac{1}{e}

Decimal

x = 0.60653 \dots, x = - 0.60653 \dots

Solution steps

ln (x^{2}) + 1 = 0

Move

1

to the right side

ln (x^{2}) = - 1

Apply log rules

x^{2} = \frac{1}{e}

Solve

x^{2} = \frac{1}{e} : x = \frac{1}{e}, x = - \frac{1}{e}

x = \frac{1}{e}, x = - \frac{1}{e}

Verify Solutions:

x = \frac{1}{e}

True

, x = - \frac{1}{e}

True

The solutions are

x = \frac{1}{e}, x = - \frac{1}{e}

lo g_{4} (x + 10) = 3

lo g_{5} (2 x + 3) = 3

lo g_{3} (2 x - 5) = 3

lo g_{\frac{1}{7}} (2 x + 5) = - 2

9^{l o g_{3} (x + 2)} = x^{2} + 12

What is the answer to ln(x^2)+1=0 ?
The answer to ln(x^2)+1=0 is x=sqrt(1/e),x=-sqrt(1/e)
Solve for x: ln(x^2)+1=0
The solution is x=sqrt(1/e),x=-sqrt(1/e)