What is the answer to 9^{log_{3}(x+2)}=x^2+12 ?

The answer to 9^{log_{3}(x+2)}=x^2+12 is x=2

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9^{log_{3}(x+2)}=x^2+12

9^{l o g_{3} (x + 2)} = x^{2} + 12

x = 2

Solution steps

9^{l o g_{3} (x + 2)} = x^{2} + 12

Apply log rules

(x + 2)^{2} = x^{2} + 12

Solve

(x + 2)^{2} = x^{2} + 12 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{10} (5 x) + lo g_{10} (x - 1) = 2

lo g_{2} (4 - x) = 9

5 x^{4} ln (x) + x^{4} = 0

4 = lo g_{10} (\frac{250}{x})

lo g_{2} (5 - x) = 3

What is the answer to 9^{log_{3}(x+2)}=x^2+12 ?
The answer to 9^{log_{3}(x+2)}=x^2+12 is x=2
Solve for x: 9^{log_{3}(x+2)}=x^2+12
The solution is x=2