What is the answer to log_{5}(x^2-2x+5)=1 ?

The answer to log_{5}(x^2-2x+5)=1 is x=2,x=0

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log_{5}(x^2-2x+5)=1

lo g_{5} (x^{2} - 2 x + 5) = 1

x = 2, x = 0

Solution steps

lo g_{5} (x^{2} - 2 x + 5) = 1

Apply log rules

x^{2} - 2 x + 5 = 5

Solve

x^{2} - 2 x + 5 = 5 : x = 2, x = 0

x = 2, x = 0

lo g_{x - 5} (49) = 2

(lo g_{2} (x))^{2} - 4 = 0

lo g_{x} (12) = \frac{1}{2}

lo g_{x} (3 x - 2) = 2

lo g_{3} (x^{2} - 4 x + 3) = 1

What is the answer to log_{5}(x^2-2x+5)=1 ?
The answer to log_{5}(x^2-2x+5)=1 is x=2,x=0
Solve for x: log_{5}(x^2-2x+5)=1
The solution is x=2,x=0