What is the answer to log_{3}(x^2-4x+3)=1 ?

The answer to log_{3}(x^2-4x+3)=1 is x=4,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(x^2-4x+3)=1

lo g_{3} (x^{2} - 4 x + 3) = 1

x = 4, x = 0

Solution steps

lo g_{3} (x^{2} - 4 x + 3) = 1

Apply log rules

x^{2} - 4 x + 3 = 3

Solve

x^{2} - 4 x + 3 = 3 : x = 4, x = 0

x = 4, x = 0

lo g_{10} (x^{2} - 15 x) = 3

4 x^{3} ln (x) + x^{3} = 0

- lo g_{3} (2 - x) = 3

ln (x^{2} - 16) = 0

- 6 lo g_{12} (x - 5) = - 6

What is the answer to log_{3}(x^2-4x+3)=1 ?
The answer to log_{3}(x^2-4x+3)=1 is x=4,x=0
Solve for x: log_{3}(x^2-4x+3)=1
The solution is x=4,x=0