What is the answer to ln(x^2-16)=0 ?

The answer to ln(x^2-16)=0 is x=sqrt(17),x=-sqrt(17)

Solve for x: ln(x^2-16)=0

The solution is x=sqrt(17),x=-sqrt(17)

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Popular >

ln (x^{2} - 16) = 0

x = 17, x = - 17

Decimal

x = 4.12310 \dots, x = - 4.12310 \dots

Solution steps

ln (x^{2} - 16) = 0

Apply log rules

x^{2} - 16 = 1

Solve

x^{2} - 16 = 1 : x = 17, x = - 17

x = 17, x = - 17

- 6 lo g_{12} (x - 5) = - 6

2 \cdot lo g_{2} (3 x - 7) = 10

2 lo g_{10} (x) - lo g_{10} (6) = lo g_{10} (486)

y, x = lo g_{10} (y)

4 ln (x^{2}) - 7 ln (x) + ln (x + 3) = 0

What is the answer to ln(x^2-16)=0 ?
The answer to ln(x^2-16)=0 is x=sqrt(17),x=-sqrt(17)
Solve for x: ln(x^2-16)=0
The solution is x=sqrt(17),x=-sqrt(17)