What is the answer to 2*log_{2}(3x-7)=10 ?

The answer to 2*log_{2}(3x-7)=10 is x=13

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2*log_{2}(3x-7)=10

2 \cdot lo g_{2} (3 x - 7) = 10

x = 13

Solution steps

2 lo g_{2} (3 x - 7) = 10

Divide both sides by

2

lo g_{2} (3 x - 7) = 5

Apply log rules

3 x - 7 = 32

Solve

3 x - 7 = 32 : x = 13

x = 13

Verify Solutions:

x = 13

True

The solution is

x = 13

2 lo g_{10} (x) - lo g_{10} (6) = lo g_{10} (486)

y, x = lo g_{10} (y)

4 ln (x^{2}) - 7 ln (x) + ln (x + 3) = 0

6 ln (x) - 3 = 2 - ln (x)

lo g_{8} (28 k - 20) + 15 = 18

What is the answer to 2*log_{2}(3x-7)=10 ?
The answer to 2*log_{2}(3x-7)=10 is x=13
Solve for x: 2*log_{2}(3x-7)=10
The solution is x=13