What is the answer to log_{7}((x-1)^2)=0 ?

The answer to log_{7}((x-1)^2)=0 is x=2,x=0

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log_{7}((x-1)^2)=0

lo g_{7} ((x - 1)^{2}) = 0

x = 2, x = 0

Solution steps

lo g_{7} ((x - 1)^{2}) = 0

Apply log rules

(x - 1)^{2} = 1

Solve

(x - 1)^{2} = 1 : x = 2, x = 0

x = 2, x = 0

3 - lo g_{10} (x + 2) = 5

(ln (x))^{2} = ln (x)

lo g_{x} (381) = - 2

(ln (x))^{2} - ln (x^{2}) + 1 = 0

lo g_{2} (3 - x) = 0

What is the answer to log_{7}((x-1)^2)=0 ?
The answer to log_{7}((x-1)^2)=0 is x=2,x=0
Solve for x: log_{7}((x-1)^2)=0
The solution is x=2,x=0