What are the solutions to the equation 2x^2-9x-18=0 ?

The solutions to the equation 2x^2-9x-18=0 are x=6,x=-3/2

Find the zeros of 2x^2-9x-18=0

The zeros of 2x^2-9x-18=0 are x=6,x=-3/2

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2 x^{2} - 9 x - 18 = 0

x = 6, x = - \frac{3}{2}

Decimal Notation

x = 6, x = - 1.5

Solution steps

2 x^{2} - 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 18) = 15

x_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 2}

x = \frac{- ( - 9 ) + 15}{2 \cdot 2} : 6

x = \frac{- ( - 9 ) - 15}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 6, x = - \frac{3}{2}

9 r^{8} - 18 r^{2} s - 24 r s^{2}

\frac{2}{11}

x^{2} - 7 (x + 6) = x + 59

x - 4 x < - 15

∣ 2 x + 3 ∣ > 7

What are the solutions to the equation 2x^2-9x-18=0 ?
The solutions to the equation 2x^2-9x-18=0 are x=6,x=-3/2
Find the zeros of 2x^2-9x-18=0
The zeros of 2x^2-9x-18=0 are x=6,x=-3/2