What is the answer to log_{2}(-x)=-5 ?

The answer to log_{2}(-x)=-5 is x=-1/32

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log_{2}(-x)=-5

lo g_{2} (- x) = - 5

x = - \frac{1}{32}

Decimal

x = - 0.03125

Solution steps

lo g_{2} (- x) = - 5

Apply log rules

- x = \frac{1}{32}

Solve

- x = \frac{1}{32} : x = - \frac{1}{32}

x = - \frac{1}{32}

\frac{( 1 - ln ( x ) )}{x ^{2}} = 0

ln (x^{2}) = - 1

x, 2 x ln (x) + x = 0

lo g_{216} (x) = - \frac{1}{3}

lo g_{10} (3 x + 7) = 2