What is the answer to 2log_{10}(x)-log_{10}(x-16)=2 ?

The answer to 2log_{10}(x)-log_{10}(x-16)=2 is x=80,x=20

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2log_{10}(x)-log_{10}(x-16)=2

2 lo g_{10} (x) - lo g_{10} (x - 16) = 2

x = 80, x = 20

Solution steps

2 lo g_{10} (x) - lo g_{10} (x - 16) = 2

Apply log rules

x^{2} = 100 (x - 16)

Solve

x^{2} = 100 (x - 16) : x = 80, x = 20

x = 80, x = 20

Verify Solutions:

x = 80

True

, x = 20

True

The solutions are

x = 80, x = 20

lo g_{10} (x^{5}) = (lo g_{10} (x^{5}))^{3}

lo g_{10} (- 2 x) + lo g_{10} (6) = 1

lo g_{10} (3 x) = 3 x

lo g_{x} (512) = \frac{3}{2}

y, lo g_{x} (y) = 2

What is the answer to 2log_{10}(x)-log_{10}(x-16)=2 ?
The answer to 2log_{10}(x)-log_{10}(x-16)=2 is x=80,x=20
Solve for x: 2log_{10}(x)-log_{10}(x-16)=2
The solution is x=80,x=20