What is the answer to log_{10}(-2x)+log_{10}(6)=1 ?

The answer to log_{10}(-2x)+log_{10}(6)=1 is x=-5/6

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log_{10}(-2x)+log_{10}(6)=1

lo g_{10} (- 2 x) + lo g_{10} (6) = 1

x = - \frac{5}{6}

Decimal

x = - 0.83333 \dots

Solution steps

lo g_{10} (- 2 x) + lo g_{10} (6) = 1

Move

lo g_{10} (6)

to the right side

lo g_{10} (- 2 x) = 1 - lo g_{10} (6)

Apply log rules

- 2 x = \frac{5}{3}

Solve

- 2 x = \frac{5}{3} : x = - \frac{5}{6}

x = - \frac{5}{6}

Verify Solutions:

x = - \frac{5}{6}

True

The solution is

x = - \frac{5}{6}

lo g_{10} (3 x) = 3 x

lo g_{x} (512) = \frac{3}{2}

y, lo g_{x} (y) = 2

ln (4) - ln (3) = 2 ln (x) - ln (x + 1)

lo g_{2 - x} (2 x^{2} - 5 x + 2) = 2

What is the answer to log_{10}(-2x)+log_{10}(6)=1 ?
The answer to log_{10}(-2x)+log_{10}(6)=1 is x=-5/6
Solve for x: log_{10}(-2x)+log_{10}(6)=1
The solution is x=-5/6